void IppDrawLine(IppByteImage& img, IppLineParam line, BYTE c)
{
    int w = img.GetWidth();
    int h = img.GetHeight();

    // (rho, ang) 파라미터를 이용하여 직선의 시작 좌표와 끝 좌표를 계산


    int x1, y1, x2, y2;
    if ((line.ang >= 0 && line.ang < PI / 4) || (line.ang >= 3 * PI / 4 && line.ang < PI))
    {
        x1 = 0;
        y1 = static_cast<int>(floor(line.rho / cos(line.ang) + 0.5));
        x2 = w - 1;
        y2 = static_cast<int>(floor((line.rho - x2 * sin(line.ang)) / cos(line.ang) + 0.5));
    }
    else
    {
        y1 = 0;
        x1 = static_cast<int>(floor(line.rho / sin(line.ang) + 0.5));
        y2 = h - 1;
        x2 = static_cast<int>(floor((line.rho - y2 * cos(line.ang)) / sin(line.ang) + 0.5));
    }

    IppDrawLine(img, x1, y1, x2, y2, c);
}

void IppDrawLine(IppByteImage& img, int x1, int y1, int x2, int y2, BYTE c)
{
    int w = img.GetWidth();
    int h = img.GetHeight();
    BYTE** ptr = img.GetPixels2D();

    // 브레제남 알고리즘(Bresenham’s Algorithm)에 의한 직선 그리기

    int dx, dy, inc_x, inc_y, fraction;

    dx = x2 - x1;
    inc_x = (dx > 0) ? 1 : -1;
    dx = abs(dx) << 1;

    dy = y2 - y1;
    inc_y = (dy > 0) ? 1 : -1;
    dy = abs(dy) << 1;

    if (x1 >= 0 && x1 < w && y1 >= 0 && y1 < h)
        ptr[y1][x1] = c;

    if (dx >= dy)
    {
        fraction = dy - (dx >> 1);

        while (x1 != x2)
        {
            if ((fraction >= 0) && (fraction || (inc_x > 0)))
            {
                fraction -= dx;
                y1 += inc_y;
            }

            fraction += dy;
            x1 += inc_x;

            if (x1 >= 0 && x1 < w && y1 >= 0 && y1 < h)
                ptr[y1][x1] = c;
        }
    }
    else
    {
        fraction = dx - (dy >> 1);

        while (y1 != y2)
        {
            if ((fraction >= 0) && (fraction || (inc_y > 0)))
            {
                fraction -= dy;
                x1 += inc_x;
            }

            fraction += dx;
            y1 += inc_y;

            if (x1 >= 0 && x1 < w && y1 >= 0 && y1 < h)
            ptr[y1][x1] = c;
        }
    }
}